Method
Split
Warning
This item was deprecated in version 2019r2. Please use String.Split as a replacement.
Description
Creates a one-dimensional array from the String.
Usage
result = source.Split([delimiter])
Part |
Type |
Description |
---|---|---|
result |
String array |
Array resulting from breaking source into elements using delimiter as the field delimiter. |
source |
Source string to be parsed into an array. |
|
delimiter |
Optional field delimiter used to parse Source into array elements. If delimiter is omitted, then a space is used as the delimiter. |
Notes
Use the Split function to create a new String array from a list of elements (or fields) that are separated by a delimiter. If the optional parameter, delimiter, is not passed, a single space is assumed as the delimiter. If the delimiter is an empty string, the source string is Split into characters.
Sample code
The section of code specifies the comma delimiter and the second uses the default delimiter. They place each field into an array element, producing a three-element array. The last code section parses the string into individual characters.
Var anArray() As String
Var s As String
s = "Adam,Aardvark,Accountant"
anArray = s.Split(",") ' produces 3-element array
anArray = s.Split("") ' produces array of individual characters
Compatibility
All project types on all supported operating systems.