Method

Mid

Warning

This item was deprecated in version 2019r2. Please use String.Middle as a replacement.

Description

Returns a portion of a string. The first character is numbered 1.

Usage

result = Mid(source, start [, length ])

Part	Type	Description
result	String	The portion of source from start and continuing for length characters or all remaining characters if length is not specified.
source	String	Required. The string from which characters are returned.
start	Integer	Required. The position of the first character to be returned.
length	Integer	Optional. The number of characters to return from source.

Notes

To determine the number of characters in a string, use the String.Length function.

The Mid function works properly with international text.

Sample code

These examples use the Mid function to return portions of a string.

Var s As String
s = Mid("This is a test", 6) ' returns "is a test"
s = Mid("This is a test", 11, 4) ' returns "test"

s = "This is a test"
s = s.Mid(11, 4) ' returns "test"

This example converts the text string in TextField1 to hex and writes the result to TextField2:

TextField2.Text = ""
For i As Integer = 1 To TextField1.Text.Length
  TextField2.Text = TextField2.Text + "&h" + Hex(Mid(TextField1.Text, i, 1).Asc)
Next

Compatibility

All project types on all supported operating systems.

Mid